Question 176267
I have a problem that reads:
If f(x)=x^2 and g(x)=x-3, find (f (open circle) g)(0)
Could you please help me figure this out?
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(fog)(x) = f[g(x)] = f[x-3] = (x-3)^2
Therefore (fog)(0) = (0-3)^2 = 9
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Cheers,
Stan H.