Question 24645
x - {{{sqrt(x)}}} = 0
implies x = {{{sqrt(x)}}}  (by adding {{{sqrt(x)}}} to both sides of the equation)
->  x^2 = x   (square both sides)
->  x^2 - x = 0
->  quadratic equation : (-(-1)+- {{{sqrt((-1)^2 - 4*1*0)}}})/(2*1)
->  = (1 +- {{{sqrt(1)}}})/2 = (1 +- 1)/2 = 0/2 or 2/2 = 0 or 1

now when graphing simply use intersection pts (0,0) and (1,1)
y=x is straight line with slope 1
as for the other, just pick a few points then draw the curve
(1/2,{{{(1/2)^2}}})=(1/2,{{{sqrt(2)}}}/2) is another good pt to start with