Question 24646
okay, so n=1000*(2^a)
and at 18:00 hrs a=6   (since 18:00=6pm is 6 hrs past noon=12:00)
so n=1000*(2^6)=1000*64=64000 at 18:00 hrs.

next,
as above I'll represent exponents with ^ symbol
k^2*l*m^2*(-kn)^2
order of operations
1. parenthesis: well nothing to do here, "-kn" is reduced
2. next exponents
   so the k is squared = k^2
      the m (not the lm) is squared = m^2
  and the -kn is squared --   
  (-kn)^2=(-k)^2 * n^2 = k^2 * n^2
3. so now comes the products (left to right)
   giving us k^2 * l * m^2 * k^2 * n^2
   grouping the k's gives us : k^4 * l * m^2 * n^2
   or in spiffy notation : {{{k^4*l*m^2*n^2}}}