Question 176167
lets complete the square
:
{{{2x^2-20x+53}}}given
:
{{{2(x^2-10x)+53}}}
:
{{{2(x^2-10x+25)+53-50}}}
:
{{{2(x-5)^2+3}}}
:
so vertex is at (5,3)
:
line of symmetry is x=5
:
minimum is at y=3
:
yes, f(5)=3 is a minimum
{{{graph(300,300,-10,10,-10,10,2(x-5)^2+3)}}}