Question 176084
{{{abs(x+10)>=20}}}
Absolute value inequalities always have two parts:
1) the original problem with the absolute value signs dropped, and
2) flip the inequality and change the sign of the right hand side
So in this case, we need to solve
{{{x+10>=20}}}
and
{{{x+10<=-20}}}
For the first one, all that is needed is to subtract 10 from both sides,
{{{x>=10}}}
Same for the second one,
{{{x<=-30}}}
I'm not sure what your solution is supposed to look like (written out as above, or drawn on a number line, or written in interval notation).  I will also write it in interval notation in case that is what you are supposed to use, but if you need to graph it on a number line, I will leave that up to you.
{{{x>=10}}} and {{{x<=-30}}} is equivalent to
(-infinity, -30) union (10, infinity)