Question 176135
Let O be the number of one peso coins.
Let F be the number of five peso coins.
Let T be the number of ten peso coins.
"Hershey has 202 pesos" 
1.{{{O+5F+10T=202}}}
"three times as many as 1 peso as 5 pesos"
2.{{{O=3*F}}}
"5 more 10 pesos than 1 peso"
3. {{{T=O+5}}}
or using eq. 2,
3. {{{T=3*F+5}}}
Use 2 and 3 and substitute into 1 and solve for F.
1.{{{O+5F+10T=202}}}
{{{3F+5F+10(3F+5)=202}}}
{{{3F+5F+30F+50=202}}}
{{{38F=152}}}
{{{F=4}}}
From 2,
2.{{{O=3*F}}}
{{{O=3*4}}}
{{{O=12}}}
From 3,
3.{{{T=3*F+5}}}
{{{T=3*4+5}}}
{{{T=17}}}
Hershey has 12 ones, 4 fives, and 17 tens.