<PRE><B>Question 176137</B>
Sara drove off going west at a speed of 40 miles per hour.
Now 2 hrs later, Jay decides to go after her and takes off at a speed of 90miles per hour. 
How long after Sara left will it be when Jay catches her?
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Sara DATA:
rate = 40 mph ; time = t hrs; distance = rt = 40t miles
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Jay DATA:
rate = 90 mph ; time = t-2; distance = rt = 90(t-2)
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Equation:
distance = distance 
40t = 90(t-2)
40t = 90t - 180
50t = 180
t = 18/5 = 3.6 hrs.
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Cheers,
Stan H.</PRE>