Question 176116
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{{{-4x-15=5y}}}, EQN 1
{{{2y=11-5x}}}, EQN 2
In EQN 1 we get,
{{{y=(-4x-15)/5=(-4/5)x-(15/5)}}}
{{{y=(-4/5)x-3}}}, EQN 3------> subst. in EQN 2:
{{{2((-4/5)x-3)=11-5x}}}
{{{(-8/5)x-6=11-5x}}}
{{{(-8/5)x+5x=11+6}}}
{{{(-8x+25x)/5=17}}}, cross multiply
{{{17x=85}}}---->{{{cross(17)x/cross(17)=cross(85)5/cross(17)}}}
{{{highlight(x=5)}}}, subst. in EQN 2:
{{{2y=11-5x}}}--->{{{y=(11-5x)/2=(-5/2)x+(11/2)}}}
{{{y=(-5/2)(5)+(11/2)=(-25/2)+(11/2)=-14/2}}}
{{{highlight(y=-7)}}}
See graph:
{{{drawing(300,300,-5,8,-8,7,grid(1),graph(300,300,-5,8,-8,7,(-4/5)x-3,(-5/2)x+(11/2)),blue(circle(5,-7,.12)))}}}--->POINT of intersection (5,-7); RED,>>> EQN 1, GREEN,>>> EQN 2
Thank you,
Jojo</pre>