Question 157372
 Please help me with this problem: 
2^5 * 2^b+3 * 2^3-b 
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The base is the same for all 3 terms, so you add the exponents.
{{{2^5*2^(b+3)*2^(3-b)}}}
={{{2^(5 + b + 3 + 3 - b)}}} 
={{{2^11}}}
=2048 (for any value of b)