Question 175881
The origin is the point (0,0). This point must
solve the equation
The line given is
{{{-4x + 3y = 12}}}
I'll put it in slope-intercept form
{{{3y = 4x + 12}}}
{{{y = (4/3)x + 4}}}
The general form is 
{{{y = mx + b}}} where {{{m}}} is the slope, so
{{{m = 4/3}}}
Going back to the general form, I can write
{{{y = (4/3)x + b}}}
To find {{{b}}}, plug (0,0) into the general equation
{{{0 = (4/3)*0 + b}}}
{{{b = 0}}}, so the answer is
{{{y = (4/3)x + 0}}}
{{{y = (4/3)x }}}