Question 175802
I have time to do one
14)
{{{((x^5) / (16y^15))^(1/4)}}}
and
I know {{{16 = 2^4}}}
I also know I can do this:
{{{((x^5) / (16y^15))^(1/4) = ((x^5)^(1/4)) / ((2^4)*(y^15))^(1/4)}}}
and
{{{((x^5)^(1/4)) / ((2^4)*(y^15))^(1/4) = (x^(5/4)) / (((2^4)^(1/4))*y^(15/4))}}}
and
{{{(x^(5/4)) / (((2^4)^(1/4))*y^(15/4)) = (x^(5/4))/(2y^(15/4)))}}}
and
{{{ (x^(5/4))/(2y^(15/4)) = (1/2)*((x) / (y^3))^(5/4)}}}
Don't lose heart- this problem is loaded
with tricky concepts, and I'm not even
sure I got it right- I've done these for years, too