Question 175714
We start by distributing through in the innermost parentheses:
{{{5x-2(3-2(x+2(x-3))) = 5x-2(3-2(x+2x-6)) = 5x-2(3-2(3x-6))}}}
Repeat:
{{{5x-2(3-2(3x-6)) = 5x-2(3-6x+12) = 5x-2(-6x+15)}}}
And one more time:
{{{5x-2(-6x+15) = 5x+12x-30 = 17x-30}}}