Question 175800
Call the number of dimes d.  Than the number of quarters can be represented by d+2.  The number of nickels is d and the number of pennies is d+2.  So then we can represent the money amount of each by
dimes - 0.10d
quarters - 0.25(d+2)
nickels = 0.05d
pennies = 0.01(d+2)
So
{{{0.10d + 0.25(d+2) + 0.05d + 0.01(d+2) = 0.93}}}
{{{0.10d + 0.25d + 0.50 + 0.05d + 0.01d + 0.02 = 0.93}}}
{{{0.41d + 0.52 = 0.93}}}
{{{0.41d = 0.41}}}
{{{d = 1}}}
So the boy had 1 dime, 3 quarters, 1 nickel and 3 pennies.