Question 24564
Well, your answer is almost correct...except for a small typo.  You have an x in the answer when there is no x in the original expression.  Here are the steps:
Factor:
{{{2w(y-2z)-y(y-2z)}}} It is not neccesary to simplify as you did because, if you look at the expression, you will see that each term has a common factor of (y-2z) and this, of course, can be factored out.
{{{(y-2z)(2w-y)}}} ...and there you have it!