Question 175660
I think you mean:  {{{(sqrt(3)/2)/((-1)/2)}}}


You do this just like you would divide any other fractions.


{{{(sqrt(3)/2)/((-1)/2)}}} is the same as {{{sqrt(3)/2}}} *[TEX \div] {{{(-1)/2}}}


As in any other problem of this type, invert the divisor and multiply:


{{{sqrt(3)/2}}} *[TEX \times] {{{2/(-1)}}}


{{{sqrt(3)/cross(2)}}} *[TEX \times] {{{cross(2)/(-1)}}}


{{{sqrt(3)/(-1) = -sqrt(3)}}}