Question 175617
Let {{{d}}}= number of 1's
Let {{{f}}}= number of 5's
Let {{{t}}}= number of 10's
given:
{{{d = 3f}}}
{{{t = f/2}}}
{{{d + 5f + 10t = 260}}}
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Substituting:
{{{3f + 5f + 10*(f/2) = 260}}}
{{{8f + 5f = 260}}}
{{{13f = 260}}}
{{{f = 20}}}
since:
{{{d = 3f}}}
{{{d = 60}}}
and
{{{t = f/2}}}
{{{t = 10}}}
The teller gave 60 1's, 20 5's, and 10 10,s
check:
{{{3f + 5f + 10*(f/2) = 260}}}
{{{3*20 + 5*20 + 10*(20/2) = 260}}}
{{{160 + 100 = 260}}}
{{{260 = 260}}}
OK