Question 175629
Here's how to find the value of a number if 
you are given the digits:
Let the 10s digit = {{{m}}}
Let the 1s digit = {{{n}}}
The value of the number is {{{10m + n}}}
Given:
{{{10n + m = 2*(10m + n) - 6}}}
{{{10n + m = 20m + 2n - 6}}}
{{{19m - 6 = 8n}}}
The key to going on from here is to realize 
that {{{m}}} and {{{n}}} are single digits
and can only be 0 - 9.
{{{m}}} can't be {{{0}}}, you can't start a 2-digit
number with {{{0}}}. I'll find {{{m}}} and
solve for {{{n}}}
{{{19m - 6 = 8n}}}
----------
m -- n
1 -- 13/8 not a digit
2 -- 4
3 -- 51/8 not a digit
4 -- 35/4 not a digit
5 -- 89/8 not a digit
6 -- 27/2 not a digit
7 -- 127/8 not a digit
8 -- 73/4 not a digit
9 -- 165/8 not a digit
The only number found is 24
check:
{{{10n + m = 2*(10m + n) - 6}}}
{{{10*4 + 2 = 2*(10*2 + 4) - 6}}}
{{{42 = 2*24 - 6}}}
{{{42 = 42}}}
OK