Question 175629
lets call our digits a and b written as ab
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now remember ab can also be written as 10a+b
and when it is reverse it is ba which can be written as 10b+a
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so with that info lets write the equation: they only gave us enough info for one equation so we are going to have to do some surmising on this one:
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10b+a=2(10a+b)-6
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10b+a=20a+2b-6
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8b-19a=-6
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the only possibilities for this scenario is digits 0-9 for both a and b.  the question is can we find an integer value for both a and b that satisfies this equation.
the value of 19a always has to be more that the value of 8b in order to get -6
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so for a=1 b can only be 1 or 2 (8-19),(16-19)...neither of which works
a=2 so 19a=38.. so we need 8b=32...8(4)=32 so we have a pair a=2 b=4.
a=3 so 19a=57...so we need 8b=51....no integer value will work
a=4 so 19a=76...so we need 8b=70....no integer value will work
a=5 so 19a=95...so we need 8b=89---> we have exhaused our possibilities here. as you can see in order for 8b=89 we would have to multiply by two digit number and as the value of 19a gets higher the same will hold true
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so we have found the only integers for which this is true and 
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they are{{{system(a=2,b=4,ab=24)}}}