Question 3062
Let the two numbers be a and b

so a+b = ab = a/b

=> a+b = ab .....(1)
and ab = a/b....(2)
from equation (2)
ab^2 = a
=> b^2 = 1
=> b = +/-1

Now sbustituting b = 1 in equation (1)
=> a + 1 = a.....this is not possible as on adding 1 to ne number does not make it equal to itself

Now substituting b = -1 in equation(1)
=> a-1 = -a
=> 2a = 1
=> a = 1/2

so a = 1/2 and b = -1