Question 175614
lets call the # of dimes and nickels , d and m, respectively
:
d=7n.....eq 1
.1d+.05n=3....eq 2
:
take d's value of 7n in eq 1 and plug it into eq 2
:
.1(7n)+.05n=3
:
.75n=3
:
{{{highlight(n=4)}}}nickels
:
{{{highlight(d=7(4)=28)}}}dimes