Question 175580
Okay I have gone over a few examples a couple of times for the following problems and I just don't understand what I am to do. 
Complete the table of values for 
Problem 1
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You are given a rule for calculating "y" based on a value of "x". 
y=1/3x+2 
x | y = 1/(3*0+2) = 1/2; (x,y) is (0,1/2)
0 | y = 1/(3*1+2) = 1/5; (x,y) is (1,1/5)| 
3 | y = 1/(3*3+2) = 1/11:(x,y) is (3,1/11)| 
6 | etc. 




Problem 2 
Using th equation 6x-3y=12 
solve for y, identify the slope, and identify the y intercept
6x-3y = 12
3y = 6x-12
y = 2x-4
slope= 2
intercept = -4
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Problem 3 
I have the points
of (4,6) and (8,18)
slope = (18-6)/(8-4) = 12/4 = 3
intercept: The form is y = mx + b , where b is the intercept.
Substitute to solve for "b":
6 = 3*4 + b
b = -6
The intercept is -6
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The slope-intercept form of the equation is:
y = 3x-6
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How am I suppose to calculate the slope (m), write the point-slope form of the line through the two points, and then write the equation in a slope-intercept form? 
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Problem 4
How am I to determine whether the point (0,1),(3,7)and (1,1),(2,3) are parallel? 
Look at the slopes:
(7-1)/(3-0) = 6/3 = 2
(3-1)/(2-1) = 2 
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The slopes are the same so the lines are parallel.
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Cheers,
Stan H.