Question 24513
both 4 and 32 scream out "powers of 2" to me...


I am assuming the 3's are coefficients rather than a cube root.


{{{(3sqrt(4))/(3sqrt(32)) }}}
{{{(sqrt(2^2))/(sqrt(2^5)) }}}
{{{sqrt((2^2)/(2^5)) }}}
{{{sqrt(1/(2^3)) }}}
or
{{{sqrt(1/8)}}}
{{{1/sqrt(8)}}}


which is {{{(1/sqrt(4*2))}}}
{{{1/(sqrt(4)sqrt(2))}}}
{{{1/(2sqrt(2))}}}


if the 3's are cube roots then we get the following:
{{{3(sqrt(2^2))/(3sqrt(2^5)) }}}
{{{3sqrt((2^2)/(2^5)) }}}
{{{((2^2)/(2^5))^(1/3) }}}
{{{(1/(2^3))^(1/3) }}}

{{{1/2}}}


jon.