Question 175454
Rate multipled by time equals distance.
{{{R*T=D}}}
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Let's call the distance to your house D.
On your bike your traveled (3/4)D.
You then walked (1/4)D.
Now let's work on time. 
"my walking time was twice my biking time"
1.{{{T[w]=2*T[b]}}}
Now we can put it all together and set up both rate equations.
Subscript b is for biking, w is for walking.
{{{R*T=D}}}
2.{{{R[b]*T[b]=D[b]=(3/4)D}}}
3.{{{R[w]*T[w]=D[w]=(1/4)D}}}
If you multiply both sides of equation 2 by 3 it will equal eq. 1,
3.{{{R[w]*T[w]=(1/4)D}}}
{{{3*R[w]*T[w]=(3/4)D}}}
2.{{{R[b]*T[b]=(3/4)D=3*R[w]*T[w]}}}
2.{{{R[b]*T[b]=3*R[w]*T[w]}}}
Now use eq. 1 and substitute for {{{T[w]}}}
 2.{{{R[b]*T[b]=3*R[w]*T[w]}}}
{{{R[b]*T[b]=3*R[w]*(2*T[b])}}}
{{{R[b]*cross(T[b])=6*R[w]*cross(T[b]))}}}
{{{R[b]=6*R[w])}}}
Your biking rate(speed) is 6 times faster than your walking rate(speed).