Question 175424
y^2+x^2+9y-6x-10=0
:
we need to complete the squares on the x and y terms
:
{{{x^2-6x+9+y^2+9y+(81/4)-9-(81/4)-10=0}}}adding and subtracting same terms to complete the square and to keep this an equivalent equation
:
{{{(x-3)^2+(y+9/2)^2=10+9+(81/4)}}}completing square
:
{{{(x-3)^2+(y+9/2)^2=157/4}}}combining terms on right
:
radius is square root of the right side in this form.
:
so the center is (3,-9/2) and the radius is {{{sqrt(157/4)=6.26}}}