Question 175369
{{{b/(b-1) + (2b)/(b^2 - 1) }}}

{{{b/(b-1) + (2b)/((b-1)(b+1)) }}}


The LCD= (b-1)(b+1).


You must multiply numerator and denominator of the first fraction times (b+1):

{{{(b/(b-1))*((b+1)/(b+1)) + (2b)/((b-1)(b+1)) }}}


{{{(b^2 + b)/((b-1)(b+1)) + (2b)/((b-1)(b+1)) }}}

{{{(b^2 +b + 2b)/((b-1)(b+1)) }}}
{{{(b^2 +3b)/((b-1)(b+1)) }}}

{{{(b(b+3))/((b-1)(b+1)) }}}


Answer does not reduce!


R^2