Question 175395
Call the first integer x.  Then we can denote the next two by x+1 and x+2 since they are consecutive.  Then the "sum of the first two" can be written as

x + (x+1)

And "24 more than the third integer" can be written as

(x+2) + 24

Thus we have the equation

x + (x+1) = (x+2) + 24
So
2x + 1 = x + 26
Subtracting x from both sides and subtracting 1 from both sides we get

x = 25

This means that the three integers are 25, 26 and 27.