Question 175311
Two consecutive even integers such that seven times the first exceeds five times the second by 54. 
Here is what I tried.
 
let the two numbers be a and b=a+2
:
7a-5(a+2)=54
:
7a-5a-10=54
:
2a=64
:
{{{highlight(a=32)}}}
:
{{{highlight(b=32+2=34)}}}
: