Question 175233
one of the method to solve system of equation is method of elimination. 
4x+6y=38
10x+8y=60
lets eliminate x, to do so you have to multiply both equations first by 10 and second by -4 then you will get 
40x+60y=380
-40x-32y=-240
as you see you got 40x in first equation and -40x in second - opposits, after adding first equation to the second x will be eliminated:
40x-40x+60y-32y=380-240
28y=140 / divide both sides by 28
y=5

to find x substitute y=5 in either first or second equation

4x+6*5=38
4x+30=38
4x=8
x=2


If you want eliminate y you will get same results:
4x+6y=38/*8
10x+8y=60/*-6

32x+48y=304
-60x-48y=-360
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-28x=-56 / divide by -28
x=2

then 10*2+8y=60
8y=60-20
8y=40
y=5