Question 175230
The difficulty in the question is that there is a variable in the denominator of the right hand side of the equation.  Also note that something must be incorrect in your question as x = -3 is not a valid solution (can be seen by simple substitution).  The first step is to multiply both sides of the equation by 3x so that there are no more "fractions" in the question.  This yields:

3(x^2) + 3x = 2

So, converting to standard form of a quadratic, we obtain

3(x^2) + 3x - 2 = 0

Now you can use whichever method you like, such as the quadratic formula to get

x = (-3 + sqrt(33))/6 
and
x = (-3 - sqrt(33))/6