Question 175207
{{{(2x^2-32)/ (x-4)}}}
<pre>
          2x           +8
      --------------------- 
x - 4 )  2x<sup>2</sup>     - 32
         2x<sup>2</sup> -8x
        --------------------
                        8x-32
                        8x-32
                        -----
                           0
                                 
Answer: 2x+8
:
or {{{2(x^2-16)/(x-4)=2(x+4)cross((x-4))/cross((x-4))=2x+8}}}
 </pre>