Question 175169
{{{5w^3 - 2w + 10}}}divided by {{{w + 3}}}
You keep going until there's nothing left to divide
into.
1st partial result: 
{{{5w^2}}}
{{{(w + 3)*5w^2 = 5w^3 + 15w^2}}}
Subtract and you're left with {{{-15w^2}}}
2nd partial result:
{{{-15w}}}
{{{(w + 3)*(-15w) = -15w^2 - 45w}}}
Subtract and you're left with {{{43w}}}
3rd partial result:
{{{43}}}
{{{(w + 3)*43 = 43w + 129}}}
Subtract and you're left with {{{-119}}}
The answer is:
{{{5w^2 - 15w + 43 - 119/(w+3)}}}
{{{-119}}} is the remainder
{{{(w + 3)*(5w^2 - 15w + 43 - 119/(w+3))}}}
gives me the original equation