Question 175148
I think you mean:  {{{64=2^3^x}}}


Recognize that 64 is a power of 2, namely {{{64=2^6}}}.  Hence, {{{2^6=2^3^x}}} and therefore {{{3^x=6}}}


Take the log of both sides:


{{{log((3^x))=log((6))}}}


But we know that {{{log((r^s))=s*log((r))}}}, so:


{{{x*log((3))=log((6))}}} and finally,


{{{x=log((6))/log((3))}}} which is the exact answer.  Use your calculator for a numerical approximation of the appropriate precision if necessary.