Question 175102
Actually, you don't need to put it in a different form.


For any parabola described by {{{f(x)=y=ax^2+bx+c}}}, the vertex is located at <large>({{{-b/2a}}},{{{f(-b/2a)}}})</large> and the equation of the axis of symmetry is {{{x=-b/2a}}}.  Just plug in your values and do the arithmetic.