Question 175094
A number {{{x}}}


That number's square {{{x^2}}}


A number added to it's square {{{x^2+x}}}


The result is 56:  {{{x^2+x=56}}}


Put the equation into standard form and solve the quadratic:


{{{x^2+x-56=0}}}  Hint:  {{{-7*8=-56}}} and {{{-7+8=1}}}


Yes, there are two numbers that exhibit the given characteristics.