Question 175058
(x-3/2)^3 x (1/x-3)^2 

[(2x-3)/2]^3 x [(1-3x)/x]^2

= (1/8)[(2x)^3 - 3(2x)^2(3) + 3(2x)(3)^2 - (3)^3][(1/x)^3(1^3 -3(3x)+3(3x)^2-(3x)^3]

etc.
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Cheers,
Stan H.