<PRE><B>Question 175066</B>
I dont know what you 5 step method is(probably in you book) but here is how I would do it
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we have an unknown number...lets call it a
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now we must read the word problem and turn it into an equation:
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sum(meaning we will have addition involved) of the number(a) and its reciprical
(1/a) is(=) 10/3
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so 
a+(1/a)=10/3............now lets start getting rid of those fractions....multiply all terms by 3
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3a+(3/a)=10.......multiply all terms by a
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{{{3a^2+3=10a}}}....now write this in quadradic form
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{{{3a^2-10a+3=0}}} try factoring
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{{{3a-1)(a-3)}}}
:
{{{system(a=1/3,a=3)}}}
 *[invoke solve_quadratic_equation 3, -10, 3]
:
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