Question 24419
1. y = x^2 - 4x - 5
     = x^2 - 4x + 4 - 4 - 5
     = (x^2 - 4x + 4) -4 - 5
   y = (x-2)^2 - 9   Here, the vertex is at (2, -9)

2.  x = 2  (the vertical line that goes through the vertex)

3.  The graph of this function is called a parabola.  To graph a parabola, use 
    its vertex (in this case, (2, -9) ) and y-intercept (y = -5).  The y-intercept is the constant in the given equation.    Use the fact that the vertical line through the vertex is a line of symmetry.  Plot the point corresponding to the y-intercept that lies on the other side of the vertical line x = 2.  


4.  The graph is translated 2 units to the right and 9 units down.