Question 175016
{{{-6x^2+48x-48=0}}}
:
first factor out -6 out of the x square and x terms
:
{{{-6(x^2-8x)-48=0}}}
:
now take 1/2 of the x term and square it  8/2=4...{{{4^2}}}=16. we also have to add 16(-6) outside the parenthesis to keep an equivalent equation
:
{{{-6(x^2-8x+16)-48+96=0}}}
:
now factor completed square
:
{{{-6(x-8)^2+48=0}}}
:
subtract 48 from both sides
:
{{{-6(x-8)^2=-48}}}
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divide by -6 on both sides
:
{{{(x-8)^2=8}}}
:
{{{x-8=sqrt(8)}}} and {{{x-8=-sqrt(8)}}}
:
{{{x=2sqrt(2)+8}}}and {{{x=-2sqrt(2)+8}}}