Question 24349
Distributive property can be explained as follows
Consider a term {{{a(b+c)= ab+ac}}}

Similarly {{{(a+b)(c+d)}}} = {{{ac+ad+bc+bd}}}

Now your problem (4y+3)(y²+3y+1) becomes

{{{4y^3 +12y^2 +4y + 3y^2 +9y +3}}}

Adding all the like terms i.e all terms that have co-efficient {{{y^2}}} and {{{y}}}

{{{4y^3 + 15y^2 + 13y + 3}}}