<PRE><B>Question 174944</B>
log_2(2m+4) – log_2(m-1) = 3
:
subtraction of logs means divide, we can write it:
log_2{{{((2m+4)/(m-1))}}} = 3
:
Exponent equiv:
2^3 = {{{(2m+4)/(m-1)}}}
8 = {{{(2m+4)/(m-1)}}}
8(m-1) = 2m + 4
:
8m - 8 = 2m + 4
:
8m - 2m = 4 + 8
:
6m = 12
m = {{{12/6}}}
m = 2
:
:
Check solution in original problem:
log_2(2(2)+4) – log_2(2-1) = 3
log_2(8) – log_2(1) = 3
3 - 0 = 3</PRE>