Question 174947
If log_2(5) = x,
:
then the exponent equiv is
{{{2^x)}}} = 5

 simplify:
log_2((cubic root 5)/2)
:
Replace 5 with {{{2^x}}}
Cubic root of {{{2^x}}} = {{{2^(x/3)}}}
:
log_2{{{(2^(x/3)/2)}}}; about all you can do with it