Question 174921
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(2,4) and (6,-2).
First we get the {{{Slope=m}}} thru Point Slope form:
{{{m=(y[2]-y[1])/(x[2]-x[1])}}}
{{{m=(-2-4)/(6-2)=-6/4}}}
{{{m=-3/2}}}
Then via  Slope-Intercept form: {{{y=mx+b}}}
Thru points (2,4):
{{{4=(-3/cross(2)1)(cross(2)1)+b}}}
{{{4=-3+b}}}----->{{{b=4+3=7}}} Y-intercept
Thru points (6,-2):
{{{-2=(-3/cross(2)1)(cross(6)3)+b}}}
{{{-2=-9+b}}}
{{{b=-2+9=7}}}
*THEY SHOULD BE EQUAL which is good.
So,via Slope intercept form:{{{highlight(y=(-3/2)x+7)}}} Answer
See graph to  verify:
{{{drawing(300,300,-5,9,-5,9,grid(1),graph(300,300,-5,9,-5,9,(-3/2)x+7),blue(circle(2,4,.15)),blue(circle(6,-2,.15)),green(circle(0,7,.15)))}}}
Thank you
Jojo</pre>