Question 24353
I am not sure whether it is {{{4(p)^2}}} or {{{(4p)^2}}} so I am solving it based on my interpretation.
{{{(4(p)^2 - 8p)/4(p)^3}}}
Taking 4p common in both the numerator and the denominator
{{{4p ((p)^2 - 2)/(4p)(p)^2}}}
Cancelling 4p 
{{{((p)^2 - 2)/(p)^2}}}