Question 174872
 [x-5]/[x^2-4] - 3x/[4x(2-x)]
={{{((x-5)/(x-2)*(x+2)) + 3x/(4x*(x-2))}}} Note change in minus signs in 2 places.
={{{(4x*(x-5)/(4x*(x-2)*(x+2))) + (3x*(x+2))/(4x*(x-2)*(x+2))}}}
Now the DEN is the same.
={{{(4x*(x-5) + 3x*(x+2))/(4x*(x-2)*(x+2))}}}
={{{(4x^2-20x + 3x^2+6x)/(4x*(x-2)*(x+2))}}}
={{{(7x^2-14x)/(4x*(x-2)*(x+2))}}}
={{{7x*(x-2)/(4x*(x-2)*(x+2))}}}
={{{7/(4*(x+2))}}}