Question 174823
f(5) = 2*10+5 = 25
So g(f(5)) = g(25) = 25^2-10 = 625-10 = 615

g(-n) = (-n)^2-10=n^2-10
So f(g(-n)) = f(n^2-10)= 2*(n^2-10) + 5 = 2*n^2-20+5 = 2*n^2-15