Question 174791
If a telephone network is designed to carry N telephone calls simultaneously, then the number of switches needed per call must be at least log_2 N. If the network can carry 10,000 calls simultaneously, how many switches would be needed:
a)	For one call?
log(base2) 1 = 0 switches.
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b)	For 10,000 simultaneous
log(base2) 10000 = log[10,000]/log[2} = 13.28
Rounding up you get 14 switches.
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Cheers,
Stan H.