Question 174777
A coin collector had a collection of silver coins worth $205. There were 5 times as many quarters as half-dollars. There were 200 fewer dimes than quarters. How many of each kind of coin did the collector have?
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dimes,quarters,half-dollars
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Value equation: 
10d + 25q + 50h = 20500 cents
Quantity Equation:
q = 5h
d = q-200
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Rearrange:
h = (1/5)q
d = q-200
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Substitute into the Value equation to solve for q:
10(q-200) + 25q + 50(1/5)q = 20500
45q = 20700
q = 460 (# of quarters)
h = (1/5)460 = 92 (# of half-dollars)
d = 460-200 = 260 (# of dimes)
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Cheers,
Stan H.