<PRE><B>Question 174770</B>
Write the equation of the line that is parallel to the graph: Y = -4X + 5, and crosses the point (3, 6)
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Parallel lines have the same slope.  The eqn is in slope-intercept form - 
y = mx+b, so its slope (m) is -4.
Then use
y-y1 = m*(x-x1) where (x1,y1) is (3,6)
y-6 = -4*(x-3)
y-6 = -4x + 12
y = -4x + 18
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