Question 174762
{{{y=a(x-1)^2+3}}}......so plug in values (3,-5) to find a
:
{{{-5=a(3-1)^2+3}}}
:
{{{-5=a(2)^2+3}}}
:
{{{-5=4a+3}}}
:
{{{4a=-8}}}
:
{{{highlight(a=-2)}}}
:
{{{highlight(y=-2(x-1)^2+3)}}}
:
{{{graph(300,300,-10,10,-10,10,-2(x-1)^2+3)}}}