Question 174738
vertex form is{{{y=(x-h)^2+k}}} where (h,k) is the vertex
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so we must complete the square in order to put this equation in vertex form
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{{{y=3(x^2-12x)-101}}}factored out 3 from x terms
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{{{y=3(x^2-12x+36)-101-36}}}added 36 to set up the completion of the square and subtracted 36, outside the parenthesis, in order to retain an equivalent equation
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y=3(x-{{{highlight(6)}}})^2{{{highlight(-137)}}}completed the square
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we are now in vertex form: with a vertex of (6,-137)